C++ program to check whether given number is palindrome or not

This is a very simple program we need to be panic for this.A number is said to be palindrome if reversal of the number is equal to itself.For ex:141 is a palindrome number.To find the reverse of the number we need to get each digit of the given number.For this we shall use the number 10.By dividing the number by 10 we get the last digit as remainder and remaining digits as quotients.Now we shall write the code.

#include
#include
class palindrome
{
  public:
    int n,r,rev,temp;
    void check();
};
void palindrome :: check()
{
   rev=0,temp=n;
   while(temp>0)
    {
      r=temp%10;
      temp=temp/10;
      rev=rev*10+r;
    }
    if(rev == n)
    {
      cout<<"Given number "<<n<<" is palindrome";
    }
    else
      cout<<"Given number "<<n<<" is not palindrome";
}
void main()
{
  clrscr();
  palindrome ob;
  coutob.n;
  ob.check();
  getch();
}

Output:

palin

You can download the code:download

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About Anuroop D

Very enthusiastic about technology and likes to share my knowledge through blogging. Has Bachelor's in Information Technology and currently pursuing my Master's in Computer Science.
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